Bewegliches Hindernis - Brägel ist zurück: Lebenshilfe für Hobby-Radsportler (Germ

Bewegliches Hindernis - Brägel ist zurück: Lebenshilfe für Hobby-Radsportler (Germ

Matematika Sekolah Menengah Pertama Quiss

10!
9!
8!
7!
2!

nt:pnten sya pnya siapa-,​

Quiss

10!
9!
8!
7!
2!

nt:pnten sya pnya siapa-,​

Jawab:

1. 3628800

2. 36280

3. 40320

4. 5040

5. 2

Penjelasan dengan langkah-langkah:

Rumusan faktorial:

[tex]n!=n[/tex]×[tex](n-1)[/tex]×[tex](n-2)[/tex]×[tex](n-3)[/tex]×...

Misal:

Tentukan nilai 5!

[tex]n!=n[/tex]×[tex](n-1)[/tex]×[tex](n-2)[/tex]×[tex](n-3)[/tex]×...

[tex]5!=5[/tex]×[tex](5-1)[/tex]×[tex](5-2)[/tex]×[tex](5-3)[/tex]×[tex](5-4)[/tex]

[tex]5!=(5)(4)(3)(2)(1)[/tex]

[tex]5!=120[/tex]

[tex]10!=(10)(9)(8)(7)(6)(5)(4)(3)(2)(1)[/tex]

[tex]10!=3628800[/tex]

[tex]9!=(9)(8)(7)(6)(5)(4)(3)(2)(1)[/tex]

[tex]9!=362880[/tex]

[tex]8!=(8)(7)(6)(5)(4)(3)(2)(1)[/tex]

[tex]8!=40320[/tex]

[tex]7!=(7)(6)(5)(4)(3)(2)(1)[/tex]

[tex]7!=5040[/tex]

[tex]2!=(2)(1)[/tex]

[tex]2!=2[/tex]

• 10! = . . .

= (10 × 9 × 8 × 7 × 6 × 5 × 4 × 3 × 2 × 1)

= (10 × 72 × 7 × 6 × 5 × 4 × 3 × 2 × 1)

= (10 × 504 × 6 × 5 × 4 × 3 × 2 × 1)

= (10 × 3.024 × 5 × 4 × 3 × 2 × 1)

= (10 × 15.120 × 4 × 3 × 2 × 1)

= (10 × 60.480 × 3 × 2 × 1)

= (10 × 181.440 × 2 × 1)

= (10 × 362.880 × 1)

= (3.628.800 × 1)

= 3.628.800

• 9! = . . .

= (9 × 8 × 7 × 6 × 5 × 4 × 3 × 2 × 1)

= (72 × 7 × 6 × 5 × 4 × 3 × 2 × 1)

= (504 × 6 × 5 × 4 × 3 × 2 × 1)

= (3.024 × 5 × 4 × 3 × 2 × 1)

= (15.120 × 4 × 3 × 2 × 1)

= (60.480 × 3 × 2 × 1)

= (181.440 × 2 × 1)

= (362.880 × 1)

= 362.880

• 8! = . . .

= (8 × 7 × 6 × 5 × 4 × 3 × 2 × 1)

= (56 × 6 × 5 × 4 × 3 × 2 × 1)

= (336 × 5 × 4 × 3 × 2 × 1)

= (1.680 × 4 × 3 × 2 × 1)

= (6.720 × 3 × 2 × 1)

= (20.160 × 2 × 1)

= (40.320 × 1)

= 40.320

• 7! = . . .

= (7 × 6 × 5 × 4 × 3 × 2 × 1)

= (42 × 5 × 4 × 3 × 2 × 1)

= (210 × 4 × 3 × 2 × 1)

= (840 × 3 × 2 × 1)

= (2.520 × 2 × 1)

= 5.040

• 2! = . . .

= (2 × 1)

= 2

[answer.2.content]